Question

a bag of m&ms has 6 red, 3 green, 5 blue, and 4 yellow m&ms. what is the probability of randomly picking: (round to 4 decimal places)
a) a yellow?
b) a blue or green?
c) an orange?

Explanation:

Step1: Calculate total number of M&M's

$6 + 3+5 + 4=18$

Step2: Calculate probability of picking a yellow

The number of yellow M&M's is 4. Probability $P=\frac{4}{18}\approx0.2222$

Step3: Calculate probability of picking a blue or green

The number of blue M&M's is 5 and green is 3. So number of favorable outcomes is $5 + 3=8$. Probability $P=\frac{8}{18}\approx0.4444$

Step4: Calculate probability of picking an orange

There are 0 orange M&M's. Probability $P = \frac{0}{18}=0$

Answer:

a) 0.2222
b) 0.4444
c) 0