Question

1. balance the equation for the combustion of ethanol by dragging the coefficients into the equation.

? c₂₅h₅₂ +? o₂ →? co₂ +? h₂o
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Explanation:

Step1: Balance carbon atoms

The number of carbon atoms in $C_{25}H_{52}$ is 25. So the coefficient of $CO_2$ should be 25 to balance the carbon atoms. The equation becomes $C_{25}H_{52}+?O_2
ightarrow25CO_2 +?H_2O$.

Step2: Balance hydrogen atoms

The number of hydrogen atoms in $C_{25}H_{52}$ is 52. In $H_2O$, since each molecule has 2 hydrogen - atoms, the coefficient of $H_2O$ should be $\frac{52}{2}=26$. The equation is now $C_{25}H_{52}+?O_2
ightarrow25CO_2 + 26H_2O$.

Step3: Balance oxygen atoms

On the right - hand side, the number of oxygen atoms in $25CO_2$ is $25\times2 = 50$, and in $26H_2O$ is 26. So the total number of oxygen atoms on the right - hand side is $50 + 26=76$. Since each $O_2$ molecule has 2 oxygen atoms, the coefficient of $O_2$ is $\frac{76}{2}=38$.

Answer:

1. $C_{25}H_{52}$, 38. $O_2$, 25. $CO_2$, 26. $H_2O$