Question

balanced or unbalanced?
determine whether or not the equation is balanced or not and write a \b\ for balanced and a \u\ for unbalanced
______ 1. \\(\ce{ch_{4} + o_{2} \
ightarrow co_{2} + 2 h_{2}o}\\)
______ 2. \\(\ce{ag_{2}o \
ightarrow ag + o_{2}}\\)
______ 3. \\(\ce{nabr + caf_{2} \
ightarrow naf + cabr_{2}}\\)
______ 4. \\(\ce{2 na + 2 h_{2}o \
ightarrow 2 naoh + h_{2}}\\)
______ 5. \\(\ce{4 p + 5 o_{2} \
ightarrow 2 p_{2}o_{5}}\\)
______ 6. \\(\ce{kclo_{3} \
ightarrow kcl + o_{2}}\\)
______ 7. \\(\ce{4 fe + 3 o_{2} \
ightarrow 2 fe_{2}o_{3}}\\)
______ 8. \\(\ce{sno_{2} + 2 h_{2} \
ightarrow sn + 2 h_{2}o}\\)

Explanation:

Step1: Count atoms for Eq1

C: 1 on both sides; H: 4 on left, $2\times2=4$ on right; O: 2 on left, $2 + 2=4$ on right.

Step2: Count atoms for Eq2

Ag: 2 on left, 1 on right; O: 1 on left, 2 on right.

Step3: Count atoms for Eq3

Na:1 on left,1 on right; Br:1 on left,2 on right; Ca:1 on both; F:2 on left,1 on right.

Step4: Count atoms for Eq4

Na:2 on both sides; H: $2\times2=4$ on left, $2\times1 + 2=4$ on right; O:2 on left, $2\times1=2$ on right.

Step5: Count atoms for Eq5

P:4 on left, $2\times2=4$ on right; O: $5\times2=10$ on left, $2\times5=10$ on right.

Step6: Count atoms for Eq6

K:1 on both; Cl:1 on both; O:3 on left,2 on right.

Step7: Count atoms for Eq7

Fe:4 on left, $2\times2=4$ on right; O: $3\times2=6$ on left, $2\times3=6$ on right.

Step8: Count atoms for Eq8

Sn:1 on both; O:2 on both; H: $2\times2=4$ on left, $2\times2=4$ on right.

Answer:

1. U
2. U
3. U
4. B
5. B
6. U
7. B
8. B