Question

do not have bands.

in a group of cepaea snails, some individuals have a banded shell and others have an unbanded shell. in this group, the gene for the shell banding trait has two alleles. the allele b is for a banded shell, and the allele b is for an unbanded shell.

a certain cepaea snail from this group has an unbanded shell. this snail has two alleles for an unbanded shell.

based on this information, click the blue words to correct any errors in the text.

this cepaea snail is heterozygous for the shell banding gene.

this cepaea snails phenotype for the shell banding gene is bb.

this cepaea snails phenotype for the shell banding trait is an unbanded shell.

Explanation:

1. The snail has two alleles for unbanded shells ($bb$), so it is homozygous, not heterozygous.
2. A phenotype is the observable trait, while $bb$ is the genotype (genetic makeup).
3. The observable trait (phenotype) of this snail is indeed an unbanded shell, so this statement is correct.

Answer:

1. Correct "heterozygous" to homozygous
2. Correct "phenotype" to genotype
3. No correction needed for this statement (it is accurate)