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Question
based on the following figure, determine the values. enter your answers in each box.$(6x+27)\degree LXB0 x = \square$ and $m\angle acb = \square$
Step1: Set angles equal (vertical angles)
$6x + 27 = 12x - 9$
Step2: Rearrange to solve for $x$
$27 + 9 = 12x - 6x$
$36 = 6x$
$x = \frac{36}{6} = 6$
Step3: Substitute $x$ to find angle
$m\angle ACB = 6(6) + 27 = 36 + 27 = 63$
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$x = 6$ and $m\angle ACB = 63$