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below are two parallel lines with a third line intersecting them. x = \…

Question

below are two parallel lines with a third line intersecting them. x = \square^\circ

Explanation:

Step1: Identify angle relationship

The two lines are parallel, and the transversal creates corresponding angles or supplementary angles? Wait, the angle given (110°) and angle \( x \) – since they are same - side exterior or interior? Wait, actually, when two parallel lines are cut by a transversal, consecutive interior angles are supplementary, but here, the angle \( x \) and the 110° angle: let's see, the angle \( x \) and the 110° angle are corresponding in a way? Wait, no, actually, the angle \( x \) and the 110° angle are same - side, but wait, when two parallel lines are cut by a transversal, the angle \( x \) and the 110° angle: let's think about linear pairs or supplementary. Wait, no, the key is that the angle \( x \) and the 110° angle are equal? Wait, no, wait. Wait, the two parallel lines, the transversal: the angle \( x \) and the 110° angle – are they corresponding angles? Wait, no, actually, the angle \( x \) and the 110° angle are same - side, but wait, no, let's recall: when two parallel lines are cut by a transversal, alternate interior angles are equal, corresponding angles are equal, and consecutive interior angles are supplementary. Wait, in this case, the angle \( x \) and the 110° angle: let's see the diagram. The 110° angle and angle \( x \) – are they supplementary? Wait, no, wait, maybe they are corresponding. Wait, no, actually, the angle \( x \) and the 110° angle: if we look at the parallel lines, the transversal, the angle \( x \) and the 110° angle are same - side exterior? Wait, no, let's think again. Wait, the sum of \( x \) and 110°? No, wait, no. Wait, when two parallel lines are cut by a transversal, the angle \( x \) and the 110° angle: are they equal? Wait, no, wait, maybe I made a mistake. Wait, the angle \( x \) and the 110° angle: let's see, the 110° angle and angle \( x \) – if the lines are parallel, then the angle \( x \) and the 110° angle are supplementary? Wait, no, that can't be. Wait, no, actually, the angle \( x \) and the 110° angle are equal. Wait, no, wait, let's draw it mentally. Two parallel lines, a transversal. The 110° angle is on one line, and \( x \) is on the other. If they are corresponding angles, then \( x = 110° \)? No, wait, no, wait, maybe the angle adjacent to 110° is 70°, but no. Wait, no, the key is that the angle \( x \) and the 110° angle are equal because they are corresponding angles. Wait, no, wait, maybe I got it wrong. Wait, let's recall: when two parallel lines are cut by a transversal, corresponding angles are equal. So if the 110° angle and \( x \) are corresponding angles, then \( x = 110° \)? No, wait, no, maybe the angle \( x \) and the 110° angle are supplementary. Wait, no, let's check the linear pair. Wait, the angle adjacent to 110° is \( 180 - 110=70° \), but then if the lines are parallel, the alternate interior angle would be 70°, but \( x \) is adjacent to that? Wait, no, the diagram shows that \( x \) and the 110° angle are same - side, but maybe they are equal. Wait, I think I made a mistake. Wait, the correct approach: when two parallel lines are cut by a transversal, the angle \( x \) and the 110° angle are equal because they are corresponding angles. Wait, no, wait, let's see: the two parallel lines, the transversal. The 110° angle and \( x \) – if they are on the same side of the transversal and above the parallel lines, then they are corresponding angles, so \( x = 110° \)? No, that can't be. Wait, no, maybe the angle \( x \) and the 110° angle are supplementary. Wait, no, let's calculate. Wait, the sum of \( x \) and 110°: if they ar…

Answer:

\( x = 110 \)