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Question
benjamin rolls a number cube labeled with the numbers 1 - 6 a total of 12 times. determine the expected value and explain your solution method. sample problem: how many of the outcomes do you expect to result in a 1? i would expect 2 out of the 12 outcomes to result in a 1. (12) = 2 how many of the outcomes do you expect to result in a number less than 6? enter the answer in the space provided. use numbers instead of words. explain your solution method. enter the answer in the space provided.
Step1: Calculate probability of rolling a 1
The probability of rolling a 1 on a fair - numbered cube is $p=\frac{1}{6}$ since there is 1 favorable outcome (rolling a 1) out of 6 possible outcomes (numbers 1 - 6).
Step2: Use expected - value formula
The expected - value formula for a binomial situation is $E(X)=np$, where $n$ is the number of trials and $p$ is the probability of success on a single trial. Here, $n = 12$ (number of rolls) and $p=\frac{1}{6}$. So, $E(X)=12\times\frac{1}{6}$.
Step3: Compute the result
$12\times\frac{1}{6}=2$.
for second part:
Step1: Calculate probability of rolling a number less than 7
The numbers on the cube are 1 - 6, so all 6 outcomes are less than 7. The probability of rolling a number less than 7 on a single roll is $p = 1$ since all 6 possible outcomes satisfy the condition.
Step2: Use expected - value formula
Using $E(X)=np$ with $n = 12$ (number of rolls) and $p = 1$, we get $E(X)=12\times1$.
Step3: Compute the result
$12\times1=12$.
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