Question

d. $-20 - 3\frac{1}{4}=14\frac{5}{8}$ (with a blank before -20, likely to find the missing number)

Explanation:

Let the unknown number be \( x \). The equation is \( x - 20 - 3\frac{1}{4}=14\frac{5}{8} \).

Step1: Combine constants on right

First, add \( 20 \) and \( 3\frac{1}{4} \) to both sides. \( x=14\frac{5}{8}+20 + 3\frac{1}{4} \)

Step2: Convert to improper fractions

\( 14\frac{5}{8}=\frac{14\times8 + 5}{8}=\frac{117}{8} \), \( 3\frac{1}{4}=\frac{3\times4+1}{4}=\frac{13}{4}=\frac{26}{8} \), \( 20=\frac{160}{8} \)

Step3: Add fractions

\( x=\frac{117}{8}+\frac{160}{8}+\frac{26}{8}=\frac{117 + 160+26}{8}=\frac{303}{8}=37\frac{7}{8} \)

Answer:

\( 37\frac{7}{8} \)