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Question
a boy drops his toy off the bunk bed. the distance to the floor is 2.5m. it takes one second to reach the floor. gravity accelerates objects on earth at 9.8 m/s². the earths gravity applies how many newton of force to the toy? what is the toys mass?
Step1: Recall the force - mass - acceleration formula
The formula for force is $F = ma$, where $F$ is force, $m$ is mass and $a$ is acceleration. In the case of an object in free - fall near the Earth's surface, the acceleration $a = g=9.8\ m/s^{2}$ (acceleration due to gravity). We need to find the mass $m$, and we know $F$ and $g$. We can re - arrange the formula to $m=\frac{F}{g}$.
Step2: Identify the values of $F$ and $g$
The acceleration due to gravity $g = 9.8\ m/s^{2}$. However, the value of the force $F$ is not given clearly in the problem statement. Assuming the problem has a value for $F$ (let's say $F$ is known), we substitute the values into the formula.
Let's assume the force $F$ is given as $F$ newtons. Then the mass $m=\frac{F}{9.8}\ kg$.
If we assume the force $F$ is $5$ newtons (since the text has an unclear '$5/$' which might be a hint for $F = 5$ N):
$m=\frac{5}{9.8}\approx0.51\ kg$
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If the force $F = 5$ N, the mass of the toy is approximately $0.51\ kg$