Question

to calculate the concentration of a dilution we use:
$c_{stock} \times v_{stock} = c_{dilute} \times v_{dilute}$
determine the final volume if a 250 ml of a 2.0 m solution was diluted to a final concentration of 1.5 m.
\\(\circ\\) 0.00030 ml
\\(\circ\\) 0.012 ml
\\(\circ\\) 330 ml
\\(\circ\\) 190 ml

Explanation:

Step1: Recall dilution formula

The dilution formula is \( C_{stock} \times V_{stock} = C_{dilute} \times V_{dilute} \). We need to find \( V_{dilute} \), so rearrange the formula: \( V_{dilute} = \frac{C_{stock} \times V_{stock}}{C_{dilute}} \)

Step2: Identify given values

\( C_{stock} = 2.0 \, M \), \( V_{stock} = 250 \, mL \), \( C_{dilute} = 1.5 \, M \)

Step3: Substitute values into formula

\( V_{dilute} = \frac{2.0 \, M \times 250 \, mL}{1.5 \, M} \)

Step4: Calculate the result

First, calculate numerator: \( 2.0 \times 250 = 500 \)
Then divide by denominator: \( \frac{500}{1.5} \approx 333.33 \, mL \). The closest option is 330 mL.

Answer:

330 mL (the option with "330 mL")