Question

calculate the exact areas of the shapes below.

Explanation:

Step1: Recall area formulas

Area of triangle $A_{triangle}=\frac{1}{2}\times base\times height$, area of parallelogram $A_{parallelogram}=base\times height$, area of square $A_{square}=side\times side$.

Step2: Calculate area of shape a

For the triangle in a, base $b = 16$ cm, height $h=9$ cm. $A_{a}=\frac{1}{2}\times16\times9=\frac{144}{2}=72$ $cm^{2}$.

Step3: Calculate area of shape b

For the parallelogram in b, base $b = 18$ m, height $h = 26$ m. $A_{b}=18\times26 = 468$ $m^{2}$.

Step4: Calculate area of shape c

For the square in c, side $s=11$ yds. $A_{c}=11\times11 = 121$ $yds^{2}$.

Step5: Calculate area of shape d

For the triangle in d, base $b=21$ (assuming the base - the horizontal side), height $h = 8$ (the perpendicular height). $A_{d}=\frac{1}{2}\times21\times8=\frac{168}{2}=84$ (units not specified in the problem - if we assume the same as the other linear - dimension units in the problem).

Answer:

a. $72$ $cm^{2}$
b. $468$ $m^{2}$
c. $121$ $yds^{2}$
d. $84$ (unspecified units)