Question

calculate the hydrogen ion concentration, h+, of an acid with a ph of 5.8. ph = - log (h+)
6.31x10^5
1.58x10^(-6)
6.31x10^(-6)
1.58x10^6

Explanation:

Step1: Rearrange the pH formula

Given $pH = -\log([H^+])$, we can rewrite it as $[H^+]=10^{-pH}$.

Step2: Substitute the pH value

Substitute $pH = 5.8$ into the formula $[H^+]=10^{-pH}$, so $[H^+]=10^{- 5.8}$.
Using a calculator, $10^{-5.8}\approx1.58\times10^{-6}$.

Answer:

$1.58\times10^{-6}$