Question

calculate the mass in grams of 1 mole of neutrons given the following conversion factors: 1 n^0 = 1.008665 amu, and 1 amu = 1.660538×10^(-24) g; and 1 mole = 6.02214×10^23 things. use units to set up this problem. we already solved the problem halfway in problem #5 above, and we know that 1 n^0 = 1.674927×10^(-24) g. now we need to convert g/1 n^0 into g/mol n^0. (----------)(----------) = 3 g/mol n^0 1 n^0 4 a. grams b. mole c. 1.008665 amu d. 1 n^0 e. 1.660538×10^(-24) g f. 1 amu g. 1.674927×10^(-24) g h. 6.074327×10^23 i. 6.02214×10^23 n^0 j. 1.008665

Explanation:

Step1: Identify the mass of 1 neutron in grams

We know that the mass of 1 neutron is $1.674927\times 10^{-24}$ g. We want to convert from mass per - neutron to mass per - mole of neutrons.

Step2: Use Avogadro's number

Avogadro's number ($N_A = 6.02214\times 10^{23}$) gives the number of entities in 1 mole. To find the mass of 1 mole of neutrons, we multiply the mass of 1 neutron by the number of neutrons in 1 mole.
We set up the conversion as $\frac{1.674927\times 10^{-24}\text{ g}}{1\text{ n}^0}\times\frac{6.02214\times 10^{23}\text{ n}^0}{1\text{ mole}}$.

So, 1: G (the mass of 1 neutron in grams), 2: I (Avogadro's number of neutrons), 3: The product of the two values which is the mass of 1 mole of neutrons, 4: B (mole).

Answer:

1. G
2. I
3. Calculate $(1.674927\times 10^{-24}\text{ g})\times(6.02214\times 10^{23})\approx1.00867$ g/mol
4. B