Question

calculate the percent composition by mass of iodine in the fictional compound shown below. include the units, but do not write the chemical formula. round the answer to 3 significant figures. be₄tc₆i₇ iodine =

Explanation:

Step1: Find molar masses of each element

Molar mass of Be: $9.012\ g/mol$, Tc: $98\ g/mol$, I: $126.90\ g/mol$ (approximate values from periodic table).

Step2: Calculate total mass of each element in the compound

• For Be: $4 \times 9.012 = 36.048\ g/mol$
• For Tc: $6 \times 98 = 588\ g/mol$
• For I: $7 \times 126.90 = 888.3\ g/mol$

Step3: Calculate molar mass of the compound

Sum the masses: $36.048 + 588 + 888.3 = 1512.348\ g/mol$

Step4: Calculate percent composition of Iodine

Percent composition = $\frac{\text{Mass of I in compound}}{\text{Molar mass of compound}} \times 100$
So, $\frac{888.3}{1512.348} \times 100 \approx 58.7\%$ (rounded to 3 significant figures)

Answer:

$58.7\%$