Question

1. calculate the specific heat for a substance if 58.0 joules are required to raise the temperature of 10.0 g from 25.0°c to 40.0°c. what is the substance?

Explanation:

Step1: Calculate temperature change

$\Delta T=40.0^{\circ}C - 25.0^{\circ}C=15.0^{\circ}C$

Step2: Use specific - heat formula

$c=\frac{Q}{m\Delta T}=\frac{58.0\ J}{10.0\ g\times15.0^{\circ}C}\approx0.39\ J/(g\cdot^{\circ}C)$

Answer:

$0.39\ J/(g\cdot^{\circ}C)$