QUESTION IMAGE
Question
calculations - put a box around the final answers to your calculations
- what was the mass of water in the beaker? (hint: subtract)
the gram per ml
- what was the density of the water in the beaker in g/ml?
(hint look at the units g/ml to know what math operation to perform)
(try to get your sig figs correct)
- what was the mass of water in the graduated cylinder? (hint: subtract)
- what was the density of the water in the graduated cylinder in g/ml?
(hint look at the units g/ml to know what math operation to perform)
(try to get your sig figs correct)
conclusions
- was the graduated cylinder or beaker a more precise tool for measuring volume? what is your reasoning?
- the actual density of tap water is 1.00 g/ml. which glassware gave you more accurate results? what is your reasoning?
- what was the total volume of water you had in your glassware today (hint: add and try to get your sig figs correct)
- which piece of glassware limits the precision of your answer to question 20?
Response
15)
Step1: Assume mass of beaker with water is $m_1$ and mass of empty beaker is $m_0$.
Mass of water in beaker = $m_1 - m_0$
Step1: Recall density formula $
ho=\frac{m}{V}$.
If mass of water is $m$ and volume is $V$, density $
ho=\frac{m}{V}$
Step1: Assume mass of graduated - cylinder with water is $m_3$ and mass of empty graduated - cylinder is $m_2$.
Mass of water in graduated cylinder = $m_3 - m_2$
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$m_1 - m_0$
16)