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an cannon ball is shot upward at a rate of 240 feet per second from gro…

Question

an cannon ball is shot upward at a rate of 240 feet per second from ground level. the cannon ball follows the path of the function h(t)=-16t² + 240t. determine when the cannon ball hits the ground. answer: the cannon ball will hit the ground after blank select an answer note: round any numerical responses to two decimal places. if there are multiple feet them with commas. question help: message instructor submit question jump to answer

Explanation:

Step1: Set height function to 0

When the cannon - ball hits the ground, $h(t)=0$. So we set $-16t^{2}+240t = 0$.

Step2: Factor out the common factor

Factor out $-16t$ from the left - hand side of the equation: $-16t(t - 15)=0$.

Step3: Solve for t

Using the zero - product property, if $ab = 0$, then either $a = 0$ or $b = 0$.
For $-16t=0$, we get $t = 0$ (this represents the initial time when the cannon - ball is shot).
For $t−15 = 0$, we get $t = 15$.

Answer:

15 seconds