Question

a cannonball launched with a horizontal velocity of 100 m/s and vertical velocity of 100 m/s hits a balloon at the top of the cannonballs trajectory. how fast is the cannonball going in each x - direction and y - direction when it hits the balloon? justify your answer.
vx, at top=
vy, at top=

Explanation:

Step1: Analyze horizontal motion

In the absence of air - resistance, there is no acceleration in the horizontal (x -) direction. So the horizontal velocity remains constant throughout the motion.
$v_{x,top}=100\ m/s$

Step2: Analyze vertical motion

At the top of the trajectory of a projectile, the vertical velocity is zero because the upward motion against gravity has been completely decelerated by the gravitational acceleration.
$v_{y,top}=0\ m/s$

Answer:

$v_{x,top}=100\ m/s$
$v_{y,top}=0\ m/s$