QUESTION IMAGE
Question
- a cell phone company charges a flat fee of $40.00 per month and an additional $20.00 per month for each phone on the plan.
a. is the relationship between the total monthly cost and the number of phones on the plan a proportional relationship? explain your thinking.
b. justify your thinking by creating a table or a graph.
Part (a)
Step1: Recall Proportional Relationship
A proportional relationship has the form \( y = kx \) (no constant term), where \( k \) is the constant of proportionality. The graph passes through the origin \((0,0)\).
Step2: Define Variables and Cost Equation
Let \( x \) = number of phones, \( y \) = total monthly cost.
Cost equation: \( y = 20x + 40 \).
Step3: Check for Proportionality
For \( x = 0 \) (no phones), \( y = 20(0) + 40 = 40
eq 0 \).
Since the equation has a constant term (\( 40 \)) and does not pass through the origin, it is not a proportional relationship.
Step1: Create a Table
Choose values for \( x \) (number of phones) and calculate \( y \) (total cost) using \( y = 20x + 40 \).
| Number of Phones (\( x \)) | Total Monthly Cost (\( y \)) |
|---|---|
| 1 | \( 20(1) + 40 = 60 \) |
| 2 | \( 20(2) + 40 = 80 \) |
| 3 | \( 20(3) + 40 = 100 \) |
Step2: Analyze the Table
In a proportional relationship, \( \frac{y}{x} \) is constant for all \( x
eq 0 \).
- For \( x = 1 \), \( \frac{60}{1} = 60 \)
- For \( x = 2 \), \( \frac{80}{2} = 40 \)
- For \( x = 3 \), \( \frac{100}{3} \approx 33.33 \)
Since \( \frac{y}{x} \) is not constant, and when \( x = 0 \), \( y = 40
eq 0 \), the relationship is not proportional. (A graph would also be a non - vertical line with a y - intercept of 40, not passing through the origin.)
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The relationship is not proportional. A proportional relationship has the form \( y = kx \) (passes through \((0,0)\)), but here \( y = 20x + 40 \), so when \( x = 0 \), \( y = 40
eq 0 \).