Question

challenge activity 3.4.1: set basics. (896312.57084946297) jump to level 1 set numbers_remaining is initialized with four numbers read from input. remove a random element from numbers_remaining. then, assign num_numbers with the number of elements in numbers_remaining. click here for example note: because sets are unordered, the set is printed using the sorted() function here for comparison. 1 numbers_remaining = set() 2 3 new_number1 = int(input()) 4 new_number2 = int(input()) 5 new_number3 = int(input()) 6 new_number4 = int(input()) 7 numbers_remaining.add(new_number1) 8 numbers_remaining.add(new_number2) 9 numbers_remaining.add(new_number3) 10 numbers_remaining.add(new_number4) 11 12... your code goes here... 13 14 print(f
umber of values remaining: {num_numbers}\)

Explanation:

Step1: Remove random set element

To remove a random element from a set, we use the pop() method, which is designed for this purpose in Python sets.

numbers_remaining.pop()

Step2: Count set elements

Assign the length of the modified set to num_numbers using the len() function, which returns the number of elements in the set.

num_numbers = len(numbers_remaining)

Answer:

The completed code (lines 11-13) is:

numbers_remaining.pop()
num_numbers = len(numbers_remaining)

When run, after inputting 4 numbers and removing one, the output will show Number of values remaining: 3 (assuming no duplicate inputs; if duplicates were entered, the count will reflect the unique remaining elements).