Question

a chemist prepares a solution of sodium hyposulfate (na₂s₂o₃) by measuring out 34.2 μmol of sodium hyposulfate into a 50. ml volumetric flask and filling the flask to the mark with water. calculate the concentration in μmol/l of the chemists sodium hyposulfate solution. be sure your answer has the correct number of significant digits.

Explanation:

Step1: Convert volume to liters

The volume of the solution is $V = 50.\text{ mL}$. Since $1\text{ L}=1000\text{ mL}$, then $V=50.\text{ mL}\times\frac{1\text{ L}}{1000\text{ mL}} = 0.050\text{ L}$.

Step2: Calculate the concentration

The concentration $C$ of a solution is given by the formula $C=\frac{n}{V}$, where $n$ is the amount of solute and $V$ is the volume of the solution. Here, $n = 34.2\ \mu\text{mol}$ and $V = 0.050\text{ L}$. So $C=\frac{34.2\ \mu\text{mol}}{0.050\text{ L}}=684\ \mu\text{mol/L}$.

Answer:

$684\ \mu\text{mol/L}$