Question

1. choose the the answer.

a container of gas has an unknown initial volume with a temperature of 10.0 °c. the final volume is found to be 3.5 l at a temperature of 30.0 °c. what was the initial volume?
0.70 l
0.9 l
3.1 l

Explanation:

Step1: Convert temps to Kelvin

$T_1 = 10.0^\circ\text{C} + 273.15 = 283.15\ \text{K}$
$T_2 = 30.0^\circ\text{C} + 273.15 = 303.15\ \text{K}$

Step2: Apply Charles's Law

Charles's Law: $\frac{V_1}{T_1} = \frac{V_2}{T_2}$
Rearrange for $V_1$: $V_1 = V_2 \times \frac{T_1}{T_2}$

Step3: Substitute values

$V_1 = 3.5\ \text{L} \times \frac{283.15\ \text{K}}{303.15\ \text{K}} \approx 3.3\ \text{L}$
(Note: Assuming the third option is 3.3 L, as the image's last option is partially obscured and matches the calculated value)

Answer:

3.3 L (corresponding to the third option in the list)