Question

1. choose the the answer.

use charles law to solve for the final celsius temperature.
$v_1 = 500.00\\ \text{ml}$
$t_1 = 40.0\\ ^\circ\text{c}$
$v_2 = 300.00\\ \text{ml}$
$t_2 = ?$

• $-85\\ ^\circ\text{c}$
• $24\\ ^\circ\text{c}$
• $188\\ ^\circ\text{c}$

Explanation:

Step1: Convert Celsius to Kelvin

$T_1 = 40.0 + 273.15 = 313.15\ \text{K}$

Step2: Apply Charles' Law formula

Charles' Law: $\frac{V_1}{T_1} = \frac{V_2}{T_2}$, rearrange to $T_2 = \frac{V_2 \times T_1}{V_1}$

Step3: Substitute values to find $T_2$ (Kelvin)

$T_2 = \frac{300.00\ \text{mL} \times 313.15\ \text{K}}{500.00\ \text{mL}} = 187.89\ \text{K}$

Step4: Convert Kelvin back to Celsius

$T_2 = 187.89 - 273.15 = -85.26\ ^\circ\text{C} \approx -85\ ^\circ\text{C}$

Answer:

-85 °C