Question

1. choose the best answer. use significant figures.

use the combined gas law to solve for the final volume.
$p_1 = 1.50\\ \text{atm}$
$v_1 = 3.00\\ \text{l}$
$t_1 = 20.0\\ ^\circ\text{c}$
$p_2 = 2.50\\ \text{atm}$
$v_2 = ?$
$t_2 = 30.0\\ ^\circ\text{c}$
$\bigcirc$ 120 l
$\bigcirc$ 1.74 l
$\bigcirc$ 1.86 l

Explanation:

Step1: Convert temp to Kelvin

$T_1 = 20.0 + 273.15 = 293.15\ \text{K}$
$T_2 = 30.0 + 273.15 = 303.15\ \text{K}$

Step2: State combined gas law

$$\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}$$

Step3: Rearrange for $V_2$

$$V_2 = \frac{P_1V_1T_2}{P_2T_1}$$

Step4: Substitute values

$$V_2 = \frac{1.50\ \text{atm} \times 3.00\ \text{L} \times 303.15\ \text{K}}{2.50\ \text{atm} \times 293.15\ \text{K}}$$

Step5: Calculate & round sig figs

$$V_2 \approx 1.86\ \text{L}$$

Answer:

1.86 L