Question

circle: $(x - h)^2+(y - k)^2=r^2$ #10 find an equation of the circle with radius $sqrt{7}$ & center $(0, 0)$

Explanation:

Step1: Identify values of h, k and r

Given center $(0,0)$ so $h = 0,k = 0$ and $r=\sqrt{7}$.

Step2: Substitute into circle - equation

Substitute $h = 0,k = 0,r=\sqrt{7}$ into $(x - h)^{2}+(y - k)^{2}=r^{2}$, we get $(x - 0)^{2}+(y - 0)^{2}=(\sqrt{7})^{2}$.

Step3: Simplify the equation

$x^{2}+y^{2}=7$.

Answer:

$x^{2}+y^{2}=7$