Question

circle h c = 3π in, circle j c = $\frac{sqrt{10}}{2}$ in, circle k c = 27.3 in. which choice shows the circles in order from greatest circumference to least circumference? circle k, circle h, circle j; circle j, circle k, circle h; circle k, circle j, circle h; circle h, circle k, circle j

Explanation:

Step1: Compare the values of circumferences.

We know that for Circle H, $C_H = 3\pi\approx3\times3.14 = 9.42$ in. For Circle J, $C_J=\frac{\sqrt{10}}{2}\approx\frac{3.162}{2}=1.581$ in. For Circle K, $C_K = 27.3$ in.

Step2: Arrange in descending order.

Since $27.3>9.42 > 1.581$, the order from greatest to least circumference is Circle K, Circle H, Circle J.

Answer:

Circle K, Circle H, Circle J