Question

a circus tent is in the shape of a square pyramid. each edge of the square base is 20 m and its slant height is 13.5 m. find the height of the tent. round the answer to the nearest tenth. (1 point)
○ 9.1 m
○ 14.8 cm
○ 24.1 cm
○ 16.8 m

Explanation:

Step1: Find base half-length

The square base edge is 20 m, so half the edge is $\frac{20}{2}=10$ m.

Step2: Use Pythagorean theorem

Let $h$ = height, $l$ = slant height = 13.5 m, $s$ = half base = 10 m. The formula is $h = \sqrt{l^2 - s^2}$.
Substitute values: $h = \sqrt{13.5^2 - 10^2}$

Step3: Calculate squared terms

$13.5^2 = 182.25$, $10^2 = 100$

Step4: Compute difference and square root

$h = \sqrt{182.25 - 100} = \sqrt{82.25} \approx 9.1$

Answer:

9.1 m