Question

click the link here to open the atom - building interactive, and click the atom square. use the interactive to answer the following questions. note: keep all atoms neutral (net charge = 0) for this exercise. be sure to select the \plus\ sign to expand the element, mass number, and net charge windows. make a he atom with a mass of 4. how many protons did you put in the nucleus? make a li atom with a mass number of 7. how many electrons did you place in the outermost orbital (ring)? make a n atom with a mass number of 14. how many neutrons are in the nucleus? make a b atom with a mass number of 11. how many electrons did you put in the second orbital (ring)?

Explanation:

Step1: Recall atomic number concept for He

The atomic number of He is 2. In a neutral atom, the number of protons equals the atomic number. So for a He atom, number of protons = 2.

Step2: Recall electron - shell configuration for Li

Li has an atomic number of 3. Its electron - shell configuration is 2,1. So in the outermost orbital, there is 1 electron.

Step3: Recall atomic number and mass - number relationship for N

The atomic number of N is 7. Mass number = number of protons+number of neutrons. Given mass number = 14 and number of protons = 7, then number of neutrons = 14 - 7=7.

Step4: Recall atomic number and electron - shell configuration for B

B has an atomic number of 5. Its electron - shell configuration is 2,3. So in the second orbital, there are 3 electrons.

Answer:

1. 2
2. 1
3. 7
4. 3