Question

co + 2 h₂ → ch₃oh 15) if you insert 2.27 moles of co, how many grams of h₂ are also used?

Explanation:

Step1: Determine mole ratio of CO to H₂

From the balanced equation $\ce{CO + 2H_{2} -> CH_{3}OH}$, the mole ratio of $\ce{CO}$ to $\ce{H_{2}}$ is $1:2$. So moles of $\ce{H_{2}}$ = 2 × moles of $\ce{CO}$.
Moles of $\ce{CO}$ = 2.27 mol, so moles of $\ce{H_{2}}$ = 2 × 2.27 mol = 4.54 mol.

Step2: Calculate mass of H₂ using molar mass

Molar mass of $\ce{H_{2}}$ is approximately 2.016 g/mol (since atomic mass of H is ~1.008, so 2 × 1.008 = 2.016).
Mass = moles × molar mass = 4.54 mol × 2.016 g/mol ≈ 9.15 g.

Answer:

Approximately 9.15 grams.