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collin is substituting $t=2$ and $t=6$ to determine if the two expressi…

Question

collin is substituting $t=2$ and $t=6$ to determine if the two expressions are equivalent:$3(4t+4)LXB0circ$ both expressions are equivalent to 33 when $t=6LXB1circ$ the expressions are not equivalent.

Explanation:

Step1: Substitute $t=2$ in first expression

$3(2)+5 = 6+5 = 11$

Step2: Substitute $t=2$ in second expression

$3(2+5) = 3(7) = 21$

Step3: Substitute $t=6$ in first expression

$3(6)+5 = 18+5 = 23$

Step4: Substitute $t=6$ in second expression

$3(6+5) = 3(11) = 33$

Step5: Compare expression values

The two expressions do not yield the same results for either substituted value, so they are not equivalent.

Answer:

D. The expressions are not equivalent.