Question

a common chemical reaction involves two ionic compounds that exchange ions to form two new compounds. the reactants and products for one of these reactions are given below. reactants: aluminum bromide and sodium phosphate products: sodium bromide and aluminum phosphate which of the following shows the correct formulas for the reactants? choose 1 answer: a albr + nap b albr + napo4 c albr3 + na3po4 d albr3 + napo4 which of the following shows the correct formulas for the products? choose 1 answer: a nabr + alp b nabr + alpo4 c nabr3 + alpo4 d nabr3 + al3po4

Explanation:

Step1: Determine aluminum bromide formula

Aluminum has a +3 charge ($Al^{3 + }$) and bromide has a - 1 charge ($Br^{-}$). To balance the charges, the formula is $AlBr_{3}$.

Step2: Determine sodium phosphate formula

Sodium has a +1 charge ($Na^{+}$) and phosphate has a - 3 charge ($PO_{4}^{3 - }$). To balance the charges, the formula is $Na_{3}PO_{4}$. So the correct reactant formulas are $AlBr_{3}+Na_{3}PO_{4}$, and the answer for reactants is C.

Step3: Determine sodium bromide formula

Sodium has a +1 charge ($Na^{+}$) and bromide has a - 1 charge ($Br^{-}$), so the formula is $NaBr$.

Step4: Determine aluminum phosphate formula

Aluminum has a +3 charge ($Al^{3 + }$) and phosphate has a - 3 charge ($PO_{4}^{3 - }$), so the formula is $AlPO_{4}$. So the correct product formulas are $NaBr + AlPO_{4}$, and the answer for products is B.

Answer:

For reactants: C. $AlBr_{3}+Na_{3}PO_{4}$
For products: B. $NaBr + AlPO_{4}$