Question

complete this assessment to review what youve learned. it will not count toward your grade. a central atom with one lone pair and three single bonds would usually have a tetrahedral shape. suppose a compound has extra pressure from its lone pairs and has a bond angle of 107 degrees. what is the difference between the bond angle predicted by the geometry and the real bond angle for this compound? (1 point) 17 degrees 0 degrees 2 degrees 25 degrees check answer remaining attempts 3

Explanation:

Step1: Recall ideal tetrahedral bond - angle

The ideal bond - angle in a tetrahedral geometry is 109.5 degrees.

Step2: Calculate the difference

The real bond - angle is 107 degrees. The difference $\Delta\theta=109.5 - 107=2.5$ degrees.

Answer:

2.5 degrees