Question

complete this equation that represents the process of nuclear fusion,
\ce{_{88}^{226}ra -> _{b}^{a}rn + _{2}^{4}he}
a:

b:

Explanation:

Step1: Conserve Mass Number (A)

In nuclear reactions, the total mass number (top number) on the left equals the sum on the right. For \(^{226}_{88}\text{Ra}
ightarrow ^{A}_{B}\text{Rn} + ^{4}_{2}\text{He}\), mass number: \(226 = A + 4\). Solve for \(A\): \(A = 226 - 4 = 222\).

Step2: Conserve Atomic Number (B)

Atomic number (bottom number) is conserved. So \(88 = B + 2\). Solve for \(B\): \(B = 88 - 2 = 86\).

Answer:

A: 222
B: 86