Question

complete the statement. if $p^3 = 27$, then $p$ is the cube root of 27. solve the equation $p^3 = 27$. $p = -9$ $p = -3$ $p = 3$ $p = 9$

Explanation:

Step1: Recall the definition of cube root

The cube root of a number \( x \) is a value \( y \) such that \( y^{3}=x \). So we need to find \( p \) where \( p^{3} = 27 \).

Step2: Calculate the cube root of 27

We know that \( 3\times3\times3=3^{3}=27 \), and also we can check the other options: \((- 9)^{3}=-729\), \((-3)^{3}=-27\), \(9^{3}=729\). So the value of \( p \) that satisfies \( p^{3}=27 \) is \( 3 \).

Answer:

\( p = 3 \) (corresponding to the option: \( p = 3 \))