QUESTION IMAGE
Question
complete the table below. for example, in the first row decide whether an atom of chlorine is mostly likely to form and then decide what type of ion it is. in the second row, write the symbol for the ion that most likely ion
element | symbol of ion | type of ion
scandium | sc$^{3+}$ | $\circ$ cation $\circ$ anion
chlorine | $\square$ | $\circ$ cation $\circ$ anionoxygen | $\square$ | $\circ$ cation $\circ$ anion
lithium | $\square$ | $\circ$ cation $\circ$ anion
strontium | $\square$ | $\circ$ cation $\circ$ anion
To solve for the most likely ions, we analyze each element based on its position in the periodic table and typical ion formation:
Chlorine (Cl)
- Step 1: Determine ion type
Chlorine is a nonmetal (halogen, Group 17). Nonmetals typically gain electrons to form anions (negative charge).
- Step 2: Determine charge
Group 17 elements (halogens) gain 1 electron to achieve a stable octet, forming \( \text{Cl}^- \).
Oxygen (O)
- Step 1: Determine ion type
Oxygen is a nonmetal (Group 16). Nonmetals form anions.
- Step 2: Determine charge
Group 16 elements gain 2 electrons to achieve a stable octet, forming \( \text{O}^{2-} \).
Lithium (Li)
- Step 1: Determine ion type
Lithium is a metal (Group 1, alkali metal). Metals typically lose electrons to form cations (positive charge).
- Step 2: Determine charge
Group 1 elements lose 1 electron to achieve a stable octet, forming \( \text{Li}^+ \).
Strontium (Sr)
- Step 1: Determine ion type
Strontium is a metal (Group 2, alkaline earth metal). Metals form cations.
- Step 2: Determine charge
Group 2 elements lose 2 electrons to achieve a stable octet, forming \( \text{Sr}^{2+} \).
Summary Table
| Element | Symbol of Ion | Type of Ion |
|---|---|---|
| Chlorine | \( \text{Cl}^- \) | Anion |
| Oxygen | \( \text{O}^{2-} \) | Anion |
| Lithium | \( \text{Li}^+ \) | Cation |
| Strontium | \( \text{Sr}^{2+} \) | Cation |
Final Answers (for each element):
- Chlorine: \( \boldsymbol{\text{Cl}^-} \) (Anion)
- Oxygen: \( \boldsymbol{\text{O}^{2-}} \) (Anion)
- Lithium: \( \boldsymbol{\text{Li}^+} \) (Cation)
- Strontium: \( \boldsymbol{\text{Sr}^{2+}} \) (Cation)
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To solve for the most likely ions, we analyze each element based on its position in the periodic table and typical ion formation:
Chlorine (Cl)
- Step 1: Determine ion type
Chlorine is a nonmetal (halogen, Group 17). Nonmetals typically gain electrons to form anions (negative charge).
- Step 2: Determine charge
Group 17 elements (halogens) gain 1 electron to achieve a stable octet, forming \( \text{Cl}^- \).
Oxygen (O)
- Step 1: Determine ion type
Oxygen is a nonmetal (Group 16). Nonmetals form anions.
- Step 2: Determine charge
Group 16 elements gain 2 electrons to achieve a stable octet, forming \( \text{O}^{2-} \).
Lithium (Li)
- Step 1: Determine ion type
Lithium is a metal (Group 1, alkali metal). Metals typically lose electrons to form cations (positive charge).
- Step 2: Determine charge
Group 1 elements lose 1 electron to achieve a stable octet, forming \( \text{Li}^+ \).
Strontium (Sr)
- Step 1: Determine ion type
Strontium is a metal (Group 2, alkaline earth metal). Metals form cations.
- Step 2: Determine charge
Group 2 elements lose 2 electrons to achieve a stable octet, forming \( \text{Sr}^{2+} \).
Summary Table
| Element | Symbol of Ion | Type of Ion |
|---|---|---|
| Chlorine | \( \text{Cl}^- \) | Anion |
| Oxygen | \( \text{O}^{2-} \) | Anion |
| Lithium | \( \text{Li}^+ \) | Cation |
| Strontium | \( \text{Sr}^{2+} \) | Cation |
Final Answers (for each element):
- Chlorine: \( \boldsymbol{\text{Cl}^-} \) (Anion)
- Oxygen: \( \boldsymbol{\text{O}^{2-}} \) (Anion)
- Lithium: \( \boldsymbol{\text{Li}^+} \) (Cation)
- Strontium: \( \boldsymbol{\text{Sr}^{2+}} \) (Cation)