Question

consider circle t with radius 24 in. and $\theta = \frac{5\pi}{6}$ radians. what is the length of minor arc sv? \
s t v \
24 in. \
$\theta$ \
\bigcirc $20\pi$ in. \
\bigcirc $28\pi$ in. \
\bigcirc $40\pi$ in. \
\bigcirc $63\pi$ in.

Explanation:

Step1: Recall arc length formula

The formula for arc length $s$ is $s = r\theta$, where $r$ is radius, $\theta$ is central angle in radians.

Step2: Substitute given values

Substitute $r=24$ in, $\theta=\frac{5\pi}{6}$:
$s = 24 \times \frac{5\pi}{6}$

Step3: Calculate the product

Simplify the expression:
$s = \frac{24 \times 5\pi}{6} = 4 \times 5\pi = 20\pi$

Answer:

20π in.