Question

consider the following data for nickel:

electronegativity	1.91
electron affinity	112. $\frac{kj}{mol}$
ionization energy	737.1 $\frac{kj}{mol}$
heat of fusion	17.2 $\frac{kj}{mol}$

you may find additional useful data in the aleks data tab.
your answer

| does the following reaction absorb or release energy? (1) $ni^{-}(g)
ightarrow ni(g)+e^{-}$ | absorb |

is it possible to calculate the amount of energy absorbed or released by reaction (1) using only the data above?	yes
if you answered yes to the previous question, enter the amount of energy absorbed or released by reaction (1):	$square kj/mol$

| does the following reaction absorb or release energy? (2) $ni(g)+e^{-}
ightarrow ni^{-}(g)$ | release |

is it possible to calculate the amount of energy absorbed or released by reaction (2) using only the data above?	yes
if you answered yes to the previous question, enter the amount of energy absorbed or released by reaction (2):	112 kj/mol

Explanation:

Step1: Analyze reaction (1)

The reaction $\text{Ni}^{-}(g)\to\text{Ni}(g)+e^{-}$ is the reverse of electron - attachment to $\text{Ni}(g)$. Removing an electron from an anion requires energy, so it absorbs energy. The energy required is equal to the electron affinity of $\text{Ni}$ but with the opposite sign.

Step2: Determine energy for reaction (1)

The electron affinity of $\text{Ni}$ is $112\ \frac{\text{kJ}}{\text{mol}}$. For the reaction $\text{Ni}^{-}(g)\to\text{Ni}(g)+e^{-}$, the energy absorbed is $112\ \frac{\text{kJ}}{\text{mol}}$.

Step3: Analyze reaction (2)

The reaction $\text{Ni}(g) + e^{-}\to\text{Ni}^{-}(g)$ is the electron - attachment process to a neutral atom. By definition, the energy change for this process is the electron affinity. Given that the electron affinity of $\text{Ni}$ is $112\ \frac{\text{kJ}}{\text{mol}}$, this reaction releases $112\ \frac{\text{kJ}}{\text{mol}}$ of energy.

Answer:

(1) absorb, yes, $112$
(2) release, yes, $112$