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consider $8x^2 - 48x = -104$. write the equation so that $a = 1$: $x^2 …

Question

consider $8x^2 - 48x = -104$. write the equation so that $a = 1$: $x^2 + \square x = \square$

Explanation:

Step1: Divide all terms by 8

$\frac{8x^2}{8} - \frac{48x}{8} = \frac{-104}{8}$

Step2: Simplify each term

$x^2 - 6x = -13$

Answer:

$x^2 + \boldsymbol{-6}x = \boldsymbol{-13}$