Question

1. construct the mole ratio needed to calculate how many moles of naoh would you expect to be produced if reaction #1 occurs.$ce{1 nahco_{3} -> 1 naoh + 1 co_{2}}$begin with the 0.0777 moles $ce{nahco_{3}}$ reacting in the experiment.$\frac{\text{a units} \times \text{c units}}{\text{e units}} = ?$ mol $ce{naoh}$i need a hintchoices:0.0777mole $ce{co_{2}}$mole $ce{naoh}$mole $ce{nahco_{3}}$12

Explanation:

Step1: Identify mole ratio from reaction

From $\ce{1 NaHCO3 -> 1 NaOH + 1 CO2}$, the mole ratio of $\ce{NaOH}$ to $\ce{NaHCO3}$ is $\frac{1\ \text{mol NaOH}}{1\ \text{mol NaHCO3}}$.

Step2: Set up unit conversion

Start with given moles of $\ce{NaHCO3}$, multiply by mole ratio.
$0.0777\ \text{mol NaHCO3} \times \frac{1\ \text{mol NaOH}}{1\ \text{mol NaHCO3}}$

Step3: Calculate result

Cancel units and compute: $0.0777 \times 1 = 0.0777$

Answer:

Filled conversion:
$0.0777\ \text{mol NaHCO}_3 \times \frac{1\ \text{mol NaOH}}{1\ \text{mol NaHCO}_3} = 0.0777\ \text{mol NaOH}$
Final moles of NaOH: $0.0777$