Question

coordinate plane with rectangle vertices (-3, 1), (3, 1), (-3, -1). multiple - choice options: (2, -2), (3, -1), (3, 1), (2, -1).

Explanation:

Step1: Analyze the rectangle's bounds

The rectangle has vertices \((-3, 1)\), \((3, 1)\), \((3, -1)\), \((-3, -1)\). So, \(x\)-range: \(-3 \leq x \leq 3\), \(y\)-range: \(-1 \leq y \leq 1\).

Step2: Check each option

• \((2, -2)\): \(y = -2 < -1\) (outside \(y\)-range).
• \((3, -1)\): \(x = 3\) (edge, but likely inside? Wait, no—wait, the rectangle's right side is at \(x = 3\), bottom at \(y = -1\). But let's check others.
• \((3, 1)\): Vertex (on edge).
• \((2, -1)\): \(x = 2\) (between \(-3\) and \(3\)), \(y = -1\) (within \(y\)-range, on bottom edge or inside). Since \((2, -1)\) has \(x\) in \([-3, 3]\) and \(y\) in \([-1, 1]\), it's inside.

Answer:

D. \((2, -1)\) (assuming the options are labeled A to D with D being \((2, -1)\); if labels differ, adjust, but the point \((2, -1)\) is inside the rectangle)