Question

the coordinates of the vertices of a triangle are j (-2, -2), k (2, -2), and l (-2, 2). triangle jkl is translated 3 units to the right and 4 units up to create triangle jkl. which graph correctly shows triangle jkl?

Explanation:

Step1: Recall translation rule

For a translation 3 units to the right and 4 units up, the rule for a point $(x,y)$ is $(x + 3,y+4)$.

Step2: Translate point J

Given $J(-2,-2)$, applying the rule: $x=-2,y = - 2$, then $J'=(-2 + 3,-2+4)=(1,2)$.

Step3: Translate point K

Given $K(2,-2)$, applying the rule: $x = 2,y=-2$, then $K'=(2 + 3,-2 + 4)=(5,2)$.

Step4: Translate point L

Given $L(-2,2)$, applying the rule: $x=-2,y = 2$, then $L'=(-2+3,2 + 4)=(1,6)$.

Answer:

The graph with vertices $J'(1,2),K'(5,2),L'(1,6)$ is the correct one. (Since no specific graph - naming is given in the problem, the coordinates of the new - triangle vertices are provided as the answer to identify the correct graph).