Question

a couple have 3 kids. the sample space of the possible gender of these kids is shown below. what is the probability that the couples kids are of both genders? a) 6/8 b) 60% c) 2/5 d) 6

Explanation:

Step1: Count total outcomes

The sample - space has 8 possible gender combinations: BBB, BBG, BGB, BGG, GBB, GBG, GGB, GGG. So, the total number of outcomes $n(S)=8$.

Step2: Count favorable outcomes

The cases where there are both genders are BBG, BGB, BGG, GBB, GBG, GGB. So, the number of favorable outcomes $n(A) = 6$.

Step3: Calculate probability

The probability $P(A)=\frac{n(A)}{n(S)}=\frac{6}{8}$.

Answer:

A. 6/8