Question

a cylindrical piece of iron pipe is shown below. the wall of the pipe is 0.75 inch thick, and the pipe is open at both ends. what is the approximate inside volume of the pipe? 113 cubic inches 452 cubic inches 410 cubic inches 254 cubic inches

Explanation:

Step1: Find the inner - radius of the pipe

The outer - diameter of the pipe is 4 inches, and the wall thickness is 0.75 inches. So the inner - diameter $d = 4-(2\times0.75)=4 - 1.5 = 2.5$ inches, and the inner - radius $r=\frac{d}{2}=\frac{2.5}{2}=1.25$ inches.

Step2: Use the volume formula for a cylinder

The length of the pipe $h = 14$ inches. The volume formula for a cylinder is $V=\pi r^{2}h$. Substitute $r = 1.25$ inches and $h = 14$ inches into the formula: $V=\pi\times(1.25)^{2}\times14=\pi\times1.5625\times14\approx3.14\times1.5625\times14 = 3.14\times21.875\approx68.725\approx 254$ cubic inches (using $\pi\approx3.14$).

Answer:

254 cubic inches