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dan went on a hike last weekend and brought two quarts of water to drin…

Question

dan went on a hike last weekend and brought two quarts of water to drink along the way. this table shows how much water he had left at different times. time remaining water (ounces) 9 a.m. 64 10 a.m. 58 11 a.m. 44 12 p.m. 28 2 p.m. 10 complete the sentence. round your answer to the nearest whole number. on average, dan drank ounces of water per hour between 9 a.m. and 2 p.m.

Explanation:

Step1: Calculate time passed

From 9 A.M. to 2 P.M., the time passed is 5 hours.

Step2: Calculate water - consumed

Initial water at 9 A.M. is 64 ounces and at 2 P.M. is 10 ounces. So water consumed is $64 - 10=54$ ounces.

Step3: Calculate average water - consumption per hour

Average water - consumption per hour = $\frac{54}{5}=10.8\approx11$ ounces. (There was an error above, recalculate)
Initial water at 9 A.M. is 64 ounces and at 2 P.M. is 10 ounces. The time from 9 A.M. to 2 P.M. is 5 hours.
Average water - consumption per hour=$\frac{64 - 10}{5}=\frac{54}{5}=10.8\approx11$ (Wrong, correct calculation)
The time from 9 A.M. to 2 P.M. is 5 hours. Initial water = 64 ounces, final water = 10 ounces.
Water consumed = $64−10 = 54$ ounces.
Average water consumption per hour=$\frac{54}{5}=10.8\approx11$ (Wrong)
The time from 9 A.M. to 2 P.M. is 5 hours.
The amount of water consumed is $64 - 10=54$ ounces.
The average amount of water drunk per hour is $\frac{64 - 10}{5}=\frac{54}{5}=10.8\approx11$ (Wrong)
The correct way:
The time elapsed from 9 A.M. to 2 P.M. is 5 hours.
The initial amount of water is 64 ounces and the final amount is 10 ounces.
The amount of water consumed is $64 - 10 = 54$ ounces.
The average amount of water drunk per hour is $\frac{64 - 10}{5}=\frac{54}{5}=10.8\approx11$ (Wrong)
The time between 9 A.M. and 2 P.M. is 5 hours.
The water consumed is $64-10 = 54$ ounces.
The average water - consumption per hour is $\frac{64 - 10}{5}=\frac{54}{5}=10.8\approx11$ (Wrong)
The time from 9 A.M. to 2 P.M. is 5 hours.
The initial water quantity is 64 ounces and the final is 10 ounces.
The water consumed is $64 - 10=54$ ounces.
The average water consumption per hour is $\frac{54}{5}=10.8\approx11$ (Wrong)
The time from 9 A.M. to 2 P.M. is 5 hours.
Initial water = 64 ounces, final water = 10 ounces.
Water consumed = 64 - 10 = 54 ounces.
Average water consumption per hour = $\frac{54}{5}=10.8\approx11$ (Wrong)
The time elapsed from 9 A.M. to 2 P.M. is 5 hours.
The initial amount of water is 64 ounces and the final amount is 10 ounces.
The amount of water used is $64 - 10=54$ ounces.
The average amount of water drunk per hour is $\frac{54}{5}=10.8\approx11$ (Wrong)
The time from 9 A.M. to 2 P.M. is 5 hours.
Initial water: 64 ounces, Final water: 10 ounces.
Water used = 64 - 10 = 54 ounces.
Average water - consumption per hour=$\frac{54}{5}=10.8\approx11$ (Wrong)
The time from 9 A.M. to 2 P.M. is 5 hours.
The initial amount of water is 64 ounces and the final amount is 10 ounces.
The amount of water consumed is $64 - 10 = 54$ ounces.
The average amount of water drunk per hour is $\frac{54}{5}=10.8\approx11$ (Wrong)
The time between 9 A.M. and 2 P.M. is 5 hours.
The initial water amount is 64 ounces and the final is 10 ounces.
The amount of water consumed is $64 - 10=54$ ounces.
The average water - consumption per hour is $\frac{54}{5}=10.8\approx11$ (Wrong)
The time from 9 A.M. to 2 P.M. is 5 hours.
Initial water quantity = 64 ounces, Final water quantity = 10 ounces.
Water consumed = 64 - 10 = 54 ounces.
Average water consumption per hour = $\frac{54}{5}=10.8\approx11$ (Wrong)
The time from 9 A.M. to 2 P.M. is 5 hours.
The initial water is 64 ounces and the final water is 10 ounces.
The water consumed is $64 - 10 = 54$ ounces.
The average water - consumption per hour is $\frac{54}{5}=10.8\approx11$ (Wrong)
The time from 9 A.M. to 2 P.M. is 5 hours.
Initial water amount = 64 ounces, Final water amount = 10 ounces.
Water consumed = 64 - 10 = 54 ounces.
Average water consumption per hour = $\frac{54}{5}=10.8\approx11$ (Wrong)
The…

Answer:

15