Question

data analysis and probability using box - and - whisker plots to compare data sets noon temperature (in fahrenheit) (a) which city had noon temperatures with a larger interquartile range (city b) (b) which city had more noon temperatures above 75 °f? (city b) (c) which city had the highest noon temperature? (select)

Explanation:

Step1: Recall inter - quartile range concept

The inter - quartile range (IQR) is the length of the box in a box - and - whisker plot, which is $Q_3 - Q_1$ (third quartile minus first quartile). Visually, we can see that the box for City B is longer than the box for City A, so City B has a larger IQR.

Step2: Analyze data above 75°F

For City A, the third - quartile ($Q_3$) is around 75°F, so about 25% of the data is above 75°F. For City B, the third - quartile is greater than 75°F, and more than 25% of the data is above 75°F. So City B has more noon temperatures above 75°F.

Step3: Identify the highest value

The end of the right - most whisker represents the maximum value. Looking at the box - and - whisker plots, the right - most whisker of City B extends further to the right than that of City A. So City B has the highest noon temperature.

Answer:

(a) City B
(b) City B
(c) City B