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QUESTION IMAGE

the data below represents an international corporations internal estima…

Question

the data below represents an international corporations internal estimates of sales (in thousands of dollars) in the coming year over time (in weeks). use a linear regression to model the data. round all your coefficients to three decimal places. then use a residual plot to determine if your model is a good fit.

week (x)1234567891011

Explanation:

Step1: Calculate sums

Let $n = 11$. Calculate $\sum_{i = 1}^{n}x_i=1 + 2+\cdots+11=\frac{11\times(11 + 1)}{2}=66$, $\sum_{i = 1}^{n}y_i=1275+2635+\cdots+2115650$, $\sum_{i = 1}^{n}x_i^2=1^2+2^2+\cdots+11^2=\frac{11\times(11 + 1)\times(2\times11 + 1)}{6}=506$, and $\sum_{i = 1}^{n}x_iy_i$.

Step2: Find slope $m$

The formula for the slope $m$ of the least - squares regression line $y=mx + b$ is $m=\frac{n\sum_{i = 1}^{n}x_iy_i-\sum_{i = 1}^{n}x_i\sum_{i = 1}^{n}y_i}{n\sum_{i = 1}^{n}x_i^2-(\sum_{i = 1}^{n}x_i)^2}$. Substitute the sums calculated in Step 1 to find $m$.

Step3: Find intercept $b$

The formula for the intercept $b$ is $b=\overline{y}-m\overline{x}$, where $\overline{x}=\frac{\sum_{i = 1}^{n}x_i}{n}$ and $\overline{y}=\frac{\sum_{i = 1}^{n}y_i}{n}$.

Step4: Calculate residuals

For each data - point $(x_i,y_i)$, calculate the residual $e_i=y_i-(mx_i + b)$.

Step5: Create residual plot

Plot the residuals $e_i$ against the $x$ - values. If the points are randomly scattered around the horizontal axis, the linear regression model is a good fit.

Answer:

The steps above outline the process to find the linear regression model and use a residual plot to determine if it is a good fit. The actual values of $m$, $b$ and the conclusion about the goodness - of - fit require the numerical sums from Step 1 to be calculated precisely. After calculating the sums:

  1. Calculate $m$ using the formula.
  2. Calculate $b$ using the formula.
  3. Calculate the residuals for each data - point.
  4. Plot the residuals against $x$ values and analyze the pattern of the points on the plot. If the points are randomly scattered, the model is a good fit; if there is a pattern (e.g., a curve), the model is not a good fit.