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Question
the data set represents wait times (in minutes) for various services at a state’s department of motor vehicles locations. which wait times are between the 25th and 75th percentiles? 18, 21, 1, 3, 5, 5, 6, 10, 1, 22, 23, 10, 6, 7, 1, 6, 6, 6, 2, 4, 14, 15, 16, 4, 19, 3, 19, 26, 3, 7, 6, 10, 9, 10, 20, 18, 20, 10, 13, 14, 11, 14, 17, 4, 27, 4, 8, 4, 26. wait times between □ minutes and □ minutes are between the 25th and 75th percentiles.
Step1: Count the number of data points
First, we count the total number of wait times. Let's list out all the data points: 18, 21, 1, 3, 5, 5, 6, 10, 1, 22, 23, 10, 6, 7, 1, 6, 6, 2, 4, 14, 15, 16, 4, 19, 3, 19, 26, 3, 7, 6, 10, 9, 10, 20, 18, 20, 10, 13, 14, 11, 14, 17, 4, 27, 4, 8, 4, 26. Let's count them: let's do it step by step. First row: 18,21,1,3,5,5,6,10,1,22,23,10,6,7,1,6,6 (17); second row: 2,4,14,15,16,4,19,3,19,26,3,7,6,10,9 (15); third row: 10,20,18,20,10,13,14,11,14,17,4,27,4,8,4,26 (16). Wait, maybe a better way: let's count the number of elements. Let's list all:
18, 21, 1, 3, 5, 5, 6, 10, 1, 22, 23, 10, 6, 7, 1, 6, 6, 2, 4, 14, 15, 16, 4, 19, 3, 19, 26, 3, 7, 6, 10, 9, 10, 20, 18, 20, 10, 13, 14, 11, 14, 17, 4, 27, 4, 8, 4, 26. Let's count: 1.18, 2.21, 3.1, 4.3, 5.5, 6.5, 7.6, 8.10, 9.1, 10.22, 11.23, 12.10, 13.6, 14.7, 15.1, 16.6, 17.6, 18.2, 19.4, 20.14, 21.15, 22.16, 23.4, 24.19, 25.3, 26.19, 27.26, 28.3, 29.7, 30.6, 31.10, 32.9, 33.10, 34.20, 35.18, 36.20, 37.10, 38.13, 39.14, 40.11, 41.14, 42.17, 43.4, 44.27, 45.4, 46.8, 47.4, 48.26. So total \( n = 48 \) data points.
Step2: Find the position of the 25th and 75th percentiles
The formula for the position of the \( p \)-th percentile is \( i = \frac{p}{100} \times n \).
For the 25th percentile (\( p = 25 \)):
\( i_{25} = \frac{25}{100} \times 48 = 0.25 \times 48 = 12 \)
For the 75th percentile (\( p = 75 \)):
\( i_{75} = \frac{75}{100} \times 48 = 0.75 \times 48 = 36 \)
Step3: Sort the data set
Now, we need to sort the data in ascending order. Let's list the sorted data:
First, list all unique values and count their frequencies:
1: appears 3 times (positions 1,9,15)
2: 1 time (18)
3: 3 times (4,25,28)
4: 5 times (19,23,43,45,47)
5: 2 times (5,6)
6: 5 times (7,13,16,17,30)
7: 2 times (14,29)
8: 1 time (46)
9: 1 time (32)
10: 5 times (8,12,31,33,37)
11: 1 time (40)
13: 1 time (38)
14: 3 times (20,39,41)
15: 1 time (21)
16: 1 time (22)
17: 1 time (42)
18: 2 times (1,35)
19: 2 times (24,26)
20: 2 times (34,36)
21: 1 time (2)
22: 1 time (10)
23: 1 time (11)
26: 2 times (27,48)
27: 1 time (44)
Now, let's sort them in ascending order:
1, 1, 1, 2, 3, 3, 3, 4, 4, 4, 4, 4, 5, 5, 6, 6, 6, 6, 6, 7, 7, 8, 9, 10, 10, 10, 10, 10, 11, 13, 14, 14, 14, 15, 16, 17, 18, 18, 19, 19, 20, 20, 21, 22, 23, 26, 26, 27
Wait, let's check the count. Let's count the sorted data:
1 (3), 2 (1), 3 (3), 4 (5), 5 (2), 6 (5), 7 (2), 8 (1), 9 (1), 10 (5), 11 (1), 13 (1), 14 (3), 15 (1), 16 (1), 17 (1), 18 (2), 19 (2), 20 (2), 21 (1), 22 (1), 23 (1), 26 (2), 27 (1). Let's sum the frequencies: 3+1=4; +3=7; +5=12; +2=14; +5=19; +2=21; +1=22; +1=23; +5=28; +1=29; +1=30; +3=33; +1=34; +1=35; +1=36; +2=38; +2=40; +2=42; +1=43; +1=44; +1=45; +2=47; +1=48. Perfect, 48 data points.
Now, the sorted list (indexes from 1 to 48):
1: 1
2: 1
3: 1
4: 2
5: 3
6: 3
7: 3
8: 4
9: 4
10: 4
11: 4
12: 4 (25th percentile position \( i_{25}=12 \), so the 12th element)
13: 5
14: 5
15: 6
16: 6
17: 6
18: 6
19: 6
20: 7
21: 7
22: 8
23: 9
24: 10
25: 10
26: 10
27: 10
28: 10
29: 11
30: 13
31: 14
32: 14
33: 14
34: 15
35: 16
36: 17 (75th percentile position \( i_{75}=36 \), so the 36th element)
37: 18
38: 18
39: 19
40: 19
41: 20
42: 20
43: 21
44: 22
45: 23
46: 26
47: 26
48: 27
Wait, let's list the sorted data with their indices (1-based):
1: 1
2: 1
3: 1
4: 2
5: 3
6: 3
7: 3
8: 4
9: 4
10: 4
11: 4
12: 4 (element at index 12: 4? Wait no, wait the frequency of 4 is 5, so the first 4 is at index 8, then 9,10,11,12. Wait, let's list the sorted data properly:…
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Wait times between \(\boldsymbol{4}\) minutes and \(\boldsymbol{17}\) minutes are between the 25th and 75th percentiles.