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date ______ pd ______ balancing chemical reactions- worksheet 2 balance…

Question

date ____ pd ____
balancing chemical reactions- worksheet 2
balance the following equations by inserting the proper coefficients.

  1. $\boldsymbol{2}LXB0ce{o_{2}}$ $

ightarrow$ $\boldsymbol{2}

$$ce{so_{3}}$ 2. $\boldsymbol{2}$$

ce{ch_{4}}$ + $\boldsymbol{3}

$$ce{o_{2}}$ $ ightarrow$ $\boldsymbol{2}$$

ce{co}$ + $\boldsymbol{4}

$$ce{h_{2}o}$ 3. $\boldsymbol{2}$$

ce{p}$ + $\boldsymbol{3}

$$ce{cl_{2}}$ $ ightarrow$ $\boldsymbol{2}$$

ce{pcl_{3}}$

  1. $\boldsymbol{2}LXB0ce{o_{2}}$ $

ightarrow$ $\boldsymbol{2}

$$ce{co_{2}}$ 5. $\boldsymbol{2}$$

ce{ch_{4}}$ + $\boldsymbol{1}

$$ce{o_{2}}$ $ ightarrow$ $\boldsymbol{2}$$

ce{ch_{3}oh}$

  1. $\boldsymbol{2}LXB0ce{br_{2}}$ $

ightarrow$ $\boldsymbol{2}

$$ce{libr}$ 7. $\boldsymbol{2}$$

ce{al_{2}o_{3}}$ $
ightarrow$ $\boldsymbol{4}$$ce{al}$ + $\boldsymbol{3}$$ce{o_{2}}$

  1. $\boldsymbol{2}LXB0ce{h_{2}o}$ $

ightarrow$ $\boldsymbol{2}$$ce{naoh}$ + $\boldsymbol{1}$$ce{h_{2}}$

  1. $\boldsymbol{6}LXB0ce{h_{2}o}$ $

ightarrow$ $\boldsymbol{1}$$ce{c_{6}h_{12}o_{6}}$ + $\boldsymbol{6}$$ce{o_{2}}$

  1. $\boldsymbol{1}LXB0ce{nacl}$ $

ightarrow$ $\boldsymbol{2}$$ce{hcl}$ + $\boldsymbol{1}$$ce{na_{2}so_{4}}$

  1. $\boldsymbol{2}LXB0ce{cacl_{2}}$ $

ightarrow$ $\boldsymbol{2}$$ce{agcl}$ + $\boldsymbol{1}$$ce{ca(no_{3})_{2}}$

  1. $\boldsymbol{2}LXB0ce{ba(oh)_{2}}$ $

ightarrow$ $\boldsymbol{1}$$ce{bacl_{2}}$ + $\boldsymbol{2}$$ce{h_{2}o}$

  1. $\boldsymbol{1}LXB0ce{naoh}$ $

ightarrow$ $\boldsymbol{1}$$ce{na_{3}po_{4}}$ + $\boldsymbol{3}$$ce{h_{2}o}$

  1. $\boldsymbol{1}LXB0ce{ki}$ $

ightarrow$ $\boldsymbol{1}$$ce{pbi_{2}}$ + $\boldsymbol{2}$$ce{kno_{3}}$

  1. $\boldsymbol{2}LXB0ce{o_{2}}$ $

ightarrow$ $\boldsymbol{2}$$ce{ch_{3}cooh}$ + $\boldsymbol{2}$$ce{h_{2}o}$

Explanation:

Step1: Verify S and O atoms

For $\ce{SO2 + O2 -> SO3}$:
S: Left=1, Right=1; O: Left=2+2=4, Right=3. Multiply $\ce{SO2}$ and $\ce{SO3}$ by 2: $2\ce{SO2 + O2 -> 2SO3}$. Now S: 2=2; O: 4+2=6=6. Correct.

Step2: Verify C, H, O atoms

For $\ce{CH4 + O2 -> CO + H2O}$:
C: 1=1; H: 4, so multiply $\ce{H2O}$ by 2: $\ce{CH4 + O2 -> CO + 2H2O}$. O: Left=2, Right=1+2=3. Multiply $\ce{O2}$ by $\frac{3}{2}$, then scale all by 2: $2\ce{CH4 + 3O2 -> 2CO + 4H2O}$. Now C:2=2; H:8=8; O:6=2+4=6. Correct.

Step3: Verify P and Cl atoms

For $\ce{P + Cl2 -> PCl3}$:
Cl: Left=2, Right=3. Multiply $\ce{Cl2}$ by 3, $\ce{PCl3}$ by 2: $\ce{P + 3Cl2 -> 2PCl3}$. Now P: Left=1, Right=2. Multiply $\ce{P}$ by 2: $2\ce{P + 3Cl2 -> 2PCl3}$. P:2=2; Cl:6=6. Correct.

Step4: Verify C and O atoms

For $\ce{CO + O2 -> CO2}$:
O: Left=1+2=3, Right=2. Multiply $\ce{CO}$ and $\ce{CO2}$ by 2: $2\ce{CO + O2 -> 2CO2}$. C:2=2; O:2+2=4=4. Correct.

Step5: Verify C, H, O atoms

For $\ce{CH4 + O2 -> CH3OH}$:
C:1=1; H:4, Right=4; O: Left=2, Right=1. Multiply $\ce{CH4}$ and $\ce{CH3OH}$ by 2: $2\ce{CH4 + O2 -> 2CH3OH}$. C:2=2; H:8=8; O:2=2. Correct.

Step6: Verify Li and Br atoms

For $\ce{Li + Br2 -> LiBr}$:
Br: Left=2, Right=1. Multiply $\ce{LiBr}$ by 2, then $\ce{Li}$ by 2: $2\ce{Li + Br2 -> 2LiBr}$. Li:2=2; Br:2=2. Correct.

Step7: Verify Al and O atoms

For $\ce{Al2O3 -> Al + O2}$:
Al: Left=2, Right=1. Multiply $\ce{Al}$ by 2: $\ce{Al2O3 -> 2Al + O2}$. O: Left=3, Right=2. Multiply $\ce{Al2O3}$ by 2, $\ce{Al}$ by 4, $\ce{O2}$ by 3: $2\ce{Al2O3 -> 4Al + 3O2}$. Al:4=4; O:6=6. Correct.

Step8: Verify Na, H, O atoms

For $\ce{Na + H2O -> NaOH + H2}$:
H: Left=2, Right=1+2=3. Multiply $\ce{H2O}$ by 2, $\ce{NaOH}$ by 2: $\ce{Na + 2H2O -> 2NaOH + H2}$. Na: Left=1, Right=2. Multiply $\ce{Na}$ by 2: $2\ce{Na + 2H2O -> 2NaOH + H2}$. Na:2=2; H:4=2+2=4; O:2=2. Correct.

Step9: Verify C, H, O atoms

For $\ce{CO2 + H2O -> C6H12O6 + O2}$:
C: Left=1, Right=6. Multiply $\ce{CO2}$ by 6: $6\ce{CO2 + H2O -> C6H12O6 + O2}$. H: Left=2, Right=12. Multiply $\ce{H2O}$ by 6: $6\ce{CO2 + 6H2O -> C6H12O6 + O2}$. O: Left=12+6=18, Right=6+2=8. Multiply $\ce{O2}$ by 6: $6\ce{CO2 + 6H2O -> C6H12O6 + 6O2}$. O:18=6+12=18. Correct.

Step10: Verify S, Na, Cl, H, O atoms

For $\ce{H2SO4 + NaCl -> HCl + Na2SO4}$:
Na: Left=1, Right=2. Multiply $\ce{NaCl}$ by 2: $\ce{H2SO4 + 2NaCl -> HCl + Na2SO4}$. Cl: Left=2, Right=1. Multiply $\ce{HCl}$ by 2: $1\ce{H2SO4 + 2NaCl -> 2HCl + 1Na2SO4}$. All atoms balanced. Correct.

Step11: Verify Ag, N, O, Ca, Cl atoms

For $\ce{AgNO3 + CaCl2 -> AgCl + Ca(NO3)2}$:
NO3: Left=1, Right=2. Multiply $\ce{AgNO3}$ by 2: $2\ce{AgNO3 + CaCl2 -> AgCl + Ca(NO3)2}$. Ag: Left=2, Right=1. Multiply $\ce{AgCl}$ by 2: $2\ce{AgNO3 + 1CaCl2 -> 2AgCl + 1Ca(NO3)2}$. All atoms balanced. Correct.

Step12: Verify H, Cl, Ba, O atoms

For $\ce{HCl + Ba(OH)2 -> BaCl2 + H2O}$:
Cl: Left=1, Right=2. Multiply $\ce{HCl}$ by 2: $2\ce{HCl + Ba(OH)2 -> BaCl2 + H2O}$. H: Left=2+2=4, Right=2. Multiply $\ce{H2O}$ by 2: $2\ce{HCl + 1Ba(OH)2 -> 1BaCl2 + 2H2O}$. All atoms balanced. Correct.

Step13: Verify H, P, O, Na atoms

For $\ce{H3PO4 + NaOH -> Na3PO4 + H2O}$:
Na: Left=1, Right=3. Multiply $\ce{NaOH}$ by 3: $\ce{H3PO4 + 3NaOH -> Na3PO4 + H2O}$. H: Left=3+3=6, Right=2. Multiply $\ce{H2O}$ by 3: $1\ce{H3PO4 + 3NaOH -> 1Na3PO4 + 3H2O}$. All atoms balanced. Correct.

Step14: Verify Pb, N, O, K, I atoms

For $\ce{Pb(NO3)2 + KI -> PbI2 + KNO3}$:
I: Left=1, Right=2. Multiply $\ce{KI}$ by 2: $\ce{Pb(NO3)2 + 2KI -> PbI2 + KNO3}$. NO3: Left=2, Right=1. Multiply $\ce{KNO3}$ by 2: $1\ce{Pb(NO3)2 + 2KI -> 1PbI2 + 2KNO3}$.…

Answer:

  1. $2\ce{SO2 + 1O2 -> 2SO3}$
  2. $2\ce{CH4 + 3O2 -> 2CO + 4H2O}$
  3. $2\ce{P + 3Cl2 -> 2PCl3}$
  4. $2\ce{CO + 1O2 -> 2CO2}$
  5. $2\ce{CH4 + 1O2 -> 2CH3OH}$
  6. $2\ce{Li + 1Br2 -> 2LiBr}$
  7. $2\ce{Al2O3 -> 4Al + 3O2}$
  8. $2\ce{Na + 2H2O -> 2NaOH + 1H2}$
  9. $6\ce{CO2 + 6H2O -> 1C6H12O6 + 6O2}$
  10. $1\ce{H2SO4 + 2NaCl -> 2HCl + 1Na2SO4}$
  11. $2\ce{AgNO3 + 1CaCl2 -> 2AgCl + 1Ca(NO3)2}$
  12. $2\ce{HCl + 1Ba(OH)2 -> 1BaCl2 + 2H2O}$
  13. $1\ce{H3PO4 + 3NaOH -> 1Na3PO4 + 3H2O}$
  14. $1\ce{Pb(NO3)2 + 2KI -> 1PbI2 + 2KNO3}$
  15. $2\ce{C2H6 + 3O2 -> 2CH3COOH + 2H2O}$