Question

day 3 (10/7)

1. write the name for h₈p₆.
2. write the name for sncl₃.
3. write the chemical formula for gallium bromide.

Explanation:

Step1: Name $H_{8}P_{6}$

This is a binary acid. First, we consider the anion $P_{6}^{8 - }$. The prefix for 6 is 'hexa -' and the element is phosphorus, so the anion is hexaphosphide. The acid name is hexaphosphoric acid.

Step2: Name $SnCl_{3}$

Tin ($Sn$) can have multiple oxidation states. Chloride has a charge of - 1. Let the oxidation state of $Sn$ be $x$. In $SnCl_{3}$, we have $x+3\times(- 1)=0$, so $x = + 3$. The name is tin(III) chloride.

Step3: Write formula for gallium bromide

Gallium ($Ga$) has a common oxidation state of + 3 and bromide ($Br$) has a charge of - 1. To balance the charges, the formula is $GaBr_{3}$.

Answer:

1. Hexaphosphoric acid
2. Tin(III) chloride
3. $GaBr_{3}$