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4. describe the acceleration of the object shown in the velocity vs. ti…

Question

  1. describe the acceleration of the object shown in the velocity vs. time graph shown below.

graph with x - axis from -10 to 10, y - axis from -10 to 10; a red horizontal arrow at y = -8
options:

  • the object is speeding up.
  • the object is not moving.

third option partially visible

Explanation:

Answer:

The velocity - time graph has a horizontal line (constant velocity? Wait, no, the red line is at \(y = - 8\), so velocity is constant at \(-8\) units. Acceleration is the rate of change of velocity. Since velocity is constant, the acceleration is \(0\). But looking at the options (even though some are faded), if we assume the graph is a horizontal line (constant velocity), acceleration is zero. But maybe the intended answer is about the slope: since the velocity - time graph is a horizontal line (slope \(= 0\)), acceleration (which is the slope of \(v - t\) graph) is \(0\). So the object has an acceleration of \(0\) (it is moving with constant velocity, not speeding up, not slowing down, just moving at a constant speed in the negative direction). If we have to choose from the visible - like "The object is not accelerating" (but since options are faded, but from the graph: velocity is constant (\(v=-8\) for all \(t\)), so acceleration \(a=\frac{\Delta v}{\Delta t}=0\). So the acceleration is zero (the object is moving with constant velocity, so no change in velocity, hence acceleration is zero).